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CRS Question, 6–36
ANSWER
Choice 4 has taken into account the kg to g to mole
conversion for 2.00 Kg of H2 and the stoichiometry. Since combustion of one
mole of H2 in the equation yields
286 kJ, the number of moles of H2 multiplied by the DH value for the equation (using H2O
(l)) will yield the correct
value.
Section
6.6: New Energy Sources