The primary way your body
produces the CO2 you just exhaled is from the combustion of glucose
C6H12O6 (molar mass = 180 g.). The balanced equation is shown
here:
C6H12O6 (aq) +
6 O2 (g) ® 6 CO2 (g) + 6 H2O (l)
If you oxidized 5.42 grams of C6H12O6 at STP conditions, how many liters of O2 did you use?
1.
0.737 L
2.
0.672 L
3.
4.05L
4.
22.4 L