nExample:
How much heat energy is absorbed when 88.0 grams of water is heated
from 5.00 degrees Celsius to 37.0 degrees
Celsius? ( c-H2O = 4186 J/ kg x C)
Take inventory first:
m = 0.0880 kg ( you must divide by 1000 to convert to kilograms)
c = 4186 J / kg x C
ΔT = 32 degrees Celsius ( 37 - 5 = 32)
Q = ?
Take inventory first:
m = 0.0880 kg ( you must divide by 1000 to convert to kilograms)
c = 4186 J / kg x C
ΔT = 32 degrees Celsius ( 37 - 5 = 32)
Q = ?
nQ
= ( 0.0880)( 4186)(32)
nQ
= 1.18 x 104 J